LiH(s)+H2O(l)=LiOH(aq)+H2(g) How many g of LiH are needed to fill a 4.1L life belt at 0.97atm and 12 degree C?

moles H2 = 0.97 x 4.1 / 0.08206 x 285 K=0.17


= moles LiH


mass LiH = 0.17 mol x 7.95 g/mol=1.4 g